(7/6)+(5/(6x))=(2/(x^2))

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Solution for (7/6)+(5/(6x))=(2/(x^2)) equation: 


D( x )

6*x = 0

x^2 = 0

6*x = 0

6*x = 0

6*x = 0 // : 6

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

5/(6*x)+7/6 = 2/(x^2) // - 2/(x^2)

5/(6*x)-(2/(x^2))+7/6 = 0

5/(6*x)-2*x^-2+7/6 = 0

5/6*x^-1-2*x^-2+7/6 = 0

t_1 = x^-1

5/6*t_1^1-2*t_1^2+7/6 = 0

5/6*t_1-2*t_1^2+7/6 = 0

DELTA = (5/6)^2-(-2*7/6*4)

DELTA = 361/36

DELTA > 0

t_1 = ((361/36)^(1/2)-5/6)/(-2*2) or t_1 = (-(361/36)^(1/2)-5/6)/(-2*2)

t_1 = -7/12 or t_1 = 1

t_1 = -7/12

x^-1+7/12 = 0

1*x^-1 = -7/12 // : 1

x^-1 = -7/12

-1 < 0

1/(x^1) = -7/12 // * x^1

1 = -7/12*x^1 // : -7/12

-12/7 = x^1

x = -12/7

t_1 = 1

x^-1-1 = 0

1*x^-1 = 1 // : 1

x^-1 = 1

-1 < 0

1/(x^1) = 1 // * x^1

1 = 1*x^1 // : 1

1 = x^1

x = 1

x in { -12/7, 1 }

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